分母分子に3角関数を含む定積分
分母分子に3角関数を含む定積分
次の積分を求めよ。
\[ \int_{0}^{\frac{\pi}{2}}\frac{\sqrt[3]{\tan x}}{\left(\sin x+\cos x\right)^{2}}dx=? \]
次の積分を求めよ。
\[ \int_{0}^{\frac{\pi}{2}}\frac{\sqrt[3]{\tan x}}{\left(\sin x+\cos x\right)^{2}}dx=? \]
\begin{align*}
\int_{0}^{\frac{\pi}{2}}\frac{\sqrt[3]{\tan x}}{\left(\sin x+\cos x\right)^{2}}dx & =\int_{0}^{\frac{\pi}{2}}\frac{\sqrt[3]{\tan x}}{\cos^{2}x\left(\tan x+1\right)^{2}}dx\\
& =\int_{0}^{\frac{\pi}{2}}\frac{\sqrt[3]{\tan x}}{\cos^{2}x\left(\tan x+1\right)^{2}}dx\\
& =\int_{0}^{\infty}\frac{\sqrt[3]{\tan x}}{\left(\tan x+1\right)^{2}}d\tan x\\
& =B\left(1+\frac{1}{3},2-\frac{1}{3}-1\right)\\
& =B\left(\frac{4}{3},\frac{2}{3}\right)\\
& =\frac{\Gamma\left(\frac{4}{3}\right)\Gamma\left(\frac{2}{3}\right)}{\Gamma\left(\frac{4}{3}+\frac{2}{3}\right)}\\
& =\frac{\Gamma\left(\frac{4}{3}\right)\Gamma\left(\frac{2}{3}\right)}{\Gamma\left(2\right)}\\
& =\frac{1}{3}\Gamma\left(\frac{1}{3}\right)\Gamma\left(1-\frac{1}{3}\right)\\
& =\frac{1}{3}\frac{\pi}{\sin\left(\frac{1}{3}\pi\right)}\\
& =\frac{2}{3\sqrt{3}}\pi\\
& =\frac{2\sqrt{3}}{9}\pi
\end{align*}
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γとπが出てくる定積分
\[
\int_{0}^{\infty}e^{-x}\log^{2}\left(x\right)dx=?
\]
tanの平方根の積分
\[
\int\sqrt{\tan x}dx=\frac{\sqrt{2}}{4}\log\left(\tan x-\sqrt{2\tan x}+1\right)-\frac{\sqrt{2}}{4}\log\left(\tan x+\sqrt{2\tan x}+1\right)+\frac{\sqrt{2}}{2}\tan^{\bullet}\left(\sqrt{2\tan x}-1\right)+\frac{\sqrt{2}}{2}\tan^{\bullet}\left(\sqrt{2\tan x}+1\right)+C
\]
πとγがでてくる定積分
\[
\int_{0}^{\infty}\frac{\sin\left(x\right)\log\left(x\right)}{x}dx=?
\]
対数のルート積分
\[
\int\log^{\frac{1}{2}}xdx=x\log^{\frac{1}{2}}x-\frac{\sqrt{\pi}}{2}erfi\left(\log^{\frac{1}{2}}x\right)+C
\]