係数が何の値か気付けるかな

係数が何の値か気付けるかな
\[ x=1+\sqrt[5]{2}+\sqrt[5]{4}+\sqrt[5]{8}+\sqrt[5]{16} \] のとき、
\[ \frac{1}{x^{5}}+\frac{5}{x^{4}}+\frac{10}{x^{3}}+\frac{10}{x^{2}}+\frac{5}{x}+1 \] の値を求めよ。
\(1,5,10,10,5,1\)は\(C\left(5,0\right),C\left(5,1\right),C\left(5,2\right),C\left(5,3\right),C\left(5,4\right),C\left(5,5\right)\)です。
\begin{align*} \frac{1}{x^{5}}+\frac{5}{x^{4}}+\frac{10}{x^{3}}+\frac{10}{x^{2}}+\frac{5}{x}+1 & =C\left(5,5\right)\left(\frac{1}{x}\right)^{5}+C\left(5,4\right)\left(\frac{1}{x}\right)^{4}+C\left(5,3\right)\left(\frac{1}{x}\right)^{3}+C\left(5,2\right)\left(\frac{1}{x}\right)^{2}+C\left(5,1\right)\left(\frac{1}{x}\right)^{1}+C\left(5,0\right)\left(\frac{1}{x}\right)^{0}\\ & =\left(1+\frac{1}{x}\right)^{5}\\ & =\left(1+\frac{1}{1+\sqrt[5]{2}+\sqrt[5]{4}+\sqrt[5]{8}+\sqrt[5]{16}}\right)^{5}\\ & =\left(1+\frac{1}{1+2^{\frac{1}{5}}+2^{\frac{2}{5}}+2^{\frac{3}{5}}+2^{\frac{4}{5}}}\right)^{5}\\ & =\left(1+\frac{1-2^{\frac{1}{5}}}{1-2^{\frac{5}{5}}}\right)^{5}\\ & =\left(1-\left(1-2^{\frac{1}{5}}\right)\right)^{5}\\ & =\left(2^{\frac{1}{5}}\right)^{5}\\ & =2 \end{align*}

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係数が何の値か気付けるかな
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