2乗のルート
2乗のルート
\(a\in\mathbb{R}\)とする。
\(a\in\mathbb{R}\)とする。
(1)
\[ \sqrt{\alpha^{2}}=\left|\alpha\right|\sqrt{\sgn^{2}\left(\alpha\right)} \](2)
\[ \sqrt{a^{2}}=\left|a\right| \](3)
\[ \sqrt{-a^{2}}=\left|a\right|i \](4)
\[ \sqrt{\pm a^{2}}=\frac{1}{2}\left(1\pm1+\left(1\mp1\right)i\right)\left|a\right| \](1)
\begin{align*} \sqrt{\alpha^{2}} & =\sqrt{\left|\alpha\right|^{2}\sgn^{2}\left(\alpha\right)}\\ & =\left|\alpha\right|\sqrt{\sgn^{2}\left(\alpha\right)} \end{align*}(1)-2
\begin{align*} \sqrt{\alpha^{2}} & =e^{\frac{1}{2}\Log\left(\alpha^{2}\right)}\\ & =e^{\frac{1}{2}\left(\ln\left|\alpha^{2}\right|+i\Arg\left(\alpha^{2}\right)\right)}\\ & =e^{\ln\left|\alpha\right|+\frac{i}{2}\Arg\left(\left|\alpha\right|^{2}\sgn^{2}\left(\alpha\right)\right)}\\ & =\left|\alpha\right|e^{\frac{i}{2}\Arg\left(\sgn^{2}\left(\alpha\right)\right)}\\ & =\left|\alpha\right|e^{\frac{1}{2}\Log\left(\sgn\left(\sgn^{2}\left(\alpha\right)\right)\right)}\\ & =\left|\alpha\right|e^{\frac{1}{2}\Log\left(\sgn^{2}\left(\alpha\right)\right)}\\ & =\left|\alpha\right|\sqrt{\sgn^{2}\left(\alpha\right)} \end{align*}(2)
\begin{align*} \sqrt{a^{2}} & =\left|a\right|\sqrt{\sgn^{2}\left(a\right)}\\ & =\left|a\right| \end{align*}(2)-2
\begin{align*} \sqrt{a^{2}} & =e^{\frac{1}{2}\Log\left(a^{2}\right)}\\ & =e^{\frac{1}{2}\ln\left|a^{2}\right|}\\ & =e^{\frac{1}{2}\ln\left|a\right|^{2}}\\ & =e^{\ln\left(\left|a\right|\right)}\\ & =\left|a\right| \end{align*}(3)
\begin{align*} \sqrt{-a^{2}} & =\sqrt{\left(ai\right)^{2}}\\ & =\left|ai\right|\sqrt{\sgn^{2}\left(ai\right)}\\ & =\left|a\right|\sqrt{\sgn^{2}\left(i\right)}\\ & =\left|a\right|i \end{align*}(3)-2
\begin{align*} \sqrt{-a^{2}} & =e^{\frac{1}{2}\Log\left(-a^{2}\right)}\\ & =e^{\frac{1}{2}\left(\ln\left|-a^{2}\right|+i\Arg\left(-a^{2}\right)\right)}\\ & =e^{\frac{1}{2}\left(\ln\left(a^{2}\right)+i\pi\right)}\\ & =ie^{\frac{1}{2}\left(\ln\left(\left|a\right|^{2}\right)\right)}\\ & =ie^{\ln\left(\left|a\right|\right)}\\ & =i\left|a\right| \end{align*}(4)
\begin{align*} \sqrt{\pm a^{2}} & =\sqrt{e^{\frac{\pi i}{2}\left(1\mp1\right)}a^{2}}\\ & =\sqrt{\left(e^{\frac{\pi i}{4}\left(1\mp1\right)}a\right)^{2}}\\ & =\left|e^{\frac{\pi i}{4}\left(1\mp1\right)}a\right|\sqrt{\sgn^{2}\left(e^{\frac{\pi i}{4}\left(1\mp1\right)}a\right)}\\ & =\left|a\right|\sqrt{e^{\frac{\pi i}{2}\left(1\mp1\right)}}\\ & =\left|a\right|e^{\frac{\pi i}{4}\left(1\mp1\right)}\\ & =\left(\frac{1+i}{\sqrt{2}}\right)\left(\frac{1\mp i}{\sqrt{2}}\right)\left|a\right|\\ & =\frac{1}{2}\left(1+\left(1\mp1\right)i\mp\left(-1\right)\right)\left|a\right|\\ & =\frac{1}{2}\left(1\pm1+\left(1\mp1\right)i\right)\left|a\right| \end{align*}(4)-2
\begin{align*} \sqrt{\pm a^{2}} & =e^{\frac{1}{2}\Log\left(\pm a^{2}\right)}\\ & =e^{\frac{1}{2}\left(\Log\left(a^{2}\right)+\Log\left(\pm1\right)\right)}\\ & =e^{\frac{1}{2}\left(\Log\left(a^{2}\right)+\frac{1\mp1}{2}i\pi\right)}\\ & =e^{\frac{i\pi}{4}}e^{\frac{\mp i\pi}{4}}e^{\frac{1}{2}\left(\Log\left(\left|a\right|^{2}\right)\right)}\\ & =e^{\frac{i\pi}{4}\left(1\mp1\right)}\left|a\right|\\ & =\frac{1}{2}\left(1\pm1+\left(1\mp1\right)i\right)\left|a\right| \end{align*}ページ情報
タイトル | 2乗のルート |
URL | https://www.nomuramath.com/xdf7ycjx/ |
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冪乗の対数
\[
\Log\alpha^{\beta}=\Re\left(\beta\right)\ln\left|\alpha\right|-\Im\left(\beta\right)\Arg\left(\alpha\right)+\mod\left(\Re\left(\beta\right)\Arg\left(\alpha\right)+\Im\left(\beta\right)\ln\left|\alpha\right|,-2\pi,\pi\right)
\]
負数の偏角と対数
\[
\Arg\alpha-\Arg\left(-\alpha\right)=2\pi H_{0}\left(\Arg\left(\alpha\right)\right)-\pi
\]
複素数の実部と虚部
\[
\Re\left(-z\right)=-\Re\left(z\right)
\]
符号関数の偏角・対数
\[
\Log\sgn\alpha=i\Arg\alpha
\]