拡張多重階乗の簡単な値
拡張多重階乗の簡単な値
(1)
\[ 0!^{n}=\frac{1}{\sqrt[n]{n}\left(\frac{1}{n}\right)!} \](2)
\[ 1!^{n}=1 \]*
\(x!^{n}\)は拡張多重階乗。(1)
\begin{align*} 0!^{n} & =n^{-\frac{1}{n}}\frac{0!}{\left(\frac{1}{n}\right)!}\cmt{\left(x\right)!^{n}=n^{\frac{x-1}{n}}\frac{\left(\frac{x}{n}\right)!}{\left(\frac{1}{n}\right)!}}\\ & =\frac{1}{\sqrt[n]{n}\left(\frac{1}{n}\right)!} \end{align*}(2)
\begin{align*} 1!^{n} & =n^{0}\frac{\left(\frac{1}{n}\right)!}{\left(\frac{1}{n}\right)!}\\ & =1\cmt{n\ne0} \end{align*}ページ情報
タイトル | 拡張多重階乗の簡単な値 |
URL | https://www.nomuramath.com/zlx1htzs/ |
SNSボタン |
2重階乗の逆数和
\[
\sum_{k=0}^{n}\frac{1}{\left(2k\right)!!}=\sqrt{e}\frac{\Gamma\left(n+1,\frac{1}{2}\right)}{\Gamma\left(n+1\right)}
\]
多重階乗の階乗表示
\[
\left(qn+r\right)!_{n}=r!_{n}n^{q}\frac{\left(q+\frac{r}{n}\right)!}{\left(\frac{r}{n}\right)!}
\]
ウォリス積分の拡張2重階乗表示
\[
\int_{0}^{\frac{\pi}{2}}\sin^{n}\theta d\theta=\frac{\left(n-1\right)!^{2}}{\left(n\right)!^{2}}\sqrt{\frac{\pi}{2}}
\]
(拡張)多重階乗の逆数和
\[
\sum_{k=0}^{n}\frac{1}{\left(ak+b\right)!_{a}}=\frac{e^{\frac{1}{a}}a^{\frac{b}{a}}\Gamma\left(\frac{b}{a}+1\right)}{b!_{a}}\left(\frac{\Gamma\left(n+\frac{b}{a}+1,\frac{1}{a}\right)}{\Gamma\left(n+\frac{b}{a}+1\right)}-\frac{\Gamma\left(\frac{b}{a},\frac{1}{a}\right)}{\Gamma\left(\frac{b}{a}\right)}\right)
\]